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A Vessel of Negligible Heat*Capacity Contains 40g of Ice in It at 0°C, 8g of Steam at 100°C is Passed into the Ice to Melt It. Find the Final Temperature of the Contents of the Vessel. - Physics

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प्रश्न

A vessel of negligible heat*capacity contains 40g of ice in it at 0°C, 8g of steam at 100°C is passed into the ice to melt it. Find the final temperature of the contents of the vessel.
(Specific latent heat of vaporization of steam = 2268 J/g, specific latent heat of fusion of ice = 336 J/f and specific heat capacity of water = 4.2 J/g°C)

टीपा लिहा

उत्तर

Assume, final temperature of contents = θ°C. Heat gained by ice at 0°C to water at 0°C + heat gained by water at 0°C to water at 0°C = Heat lost by steam at 100°C + Heat lost by water at 100°C to water at 0°C.

mLf + mcΔθ = mL + mcΔθ

40 × 336 + 40 × 4.2 × (θ - 0) = 8 × 2268 + 8 × 4.2 × (100 - θ)

13440 + 168 θ = 18144 + 3360 - 33.6 θ

168 θ + 33.60 = 8064 θ

201.6 θ = 8064 θ = 40°C

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पाठ 10: Specific Heat Capacity and Latent Heat - Short Numericals

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आईसीएसई Physics [English] Class 10
पाठ 10 Specific Heat Capacity and Latent Heat
Short Numericals | Q 9

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