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A wheel of diameter 2 m can be rotated about an axis passing through its center by a moment of force equal to 2·0 N m. What minimum force must be applied on its rim? - Physics

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प्रश्न

A wheel of diameter 2 m can be rotated about an axis passing through its center by a moment of force equal to 2·0 N m. What minimum force must be applied on its rim?

संख्यात्मक

उत्तर

Given:

Moment of force = 2·0 N m

Diameter = 2 m

So, radius = `"diameter"/2` = 1 m

Therefore, perpendicular distance d = radius = 1 m

Force f = ?

Moment of force = diameter × force

Force = `"moment of force"/"diameter"`

Force = `(2·0 " Nm")/"1 m"`

Force = 2 N

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Moment (Turning Effect) of a Force Or Torque
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पाठ 3: Force and Pressure - Numericals [पृष्ठ ५८]

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सेलिना Concise Physics [English] Class 8 ICSE
पाठ 3 Force and Pressure
Numericals | Q 4 | पृष्ठ ५८
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