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प्रश्न
A wheel of moment of inertia 2 kg m2 is rotating at a speed of 25 rad/s. Due to friction on the axis, it comes to rest in 10 minutes. Total work done by friction is ______.
पर्याय
25 J
625 J
50 J
600 J
MCQ
रिकाम्या जागा भरा
उत्तर
A wheel of moment of inertia 2 kg m2 is rotating at a speed of 25 rad/s. Due to friction on the axis, it comes to rest in 10 minutes. Total work done by friction is 625 J.
Explanation:
W = τθ = I α θ = 2αθ
`omega_2^2 = omega_1^2 - 2 alpha theta`
0 = (25)2 - 2 α θ
∴ 2 α θ = 625
∴ W = 625 J
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