Question

A wire 10 cm long carrying a current of 1.5 A is held in a uniform magneÑic field in which B = 10^-3 T. Calculate the force on the wire if it is held perpendicular to the lines of the magnetic field.

Answer 1

Given: Length of the wire l = 10 cm = 0.10 m
Current I= 1.5 A
Magnetic induction B = 10^-3T
Solution:
Force F = B I l
= 10^-3 × 1.5 × 0.10
= 1.5 × 10^-3 N.