Question

A word consists of 9 letters; 5 consonants and 4 vowels. Three letters are chosen at random. What is the probability that more than one vowel will be selected?

पर्याय

• `13/42`

• `17/42`

• `5/42`

• `3/14`

Answer 1

`17/42`

Explanation:
3 letters can be chosen out of 9 letters in `""^9C_3` ways
More than one vowels (2 vowels + 1 consonant or 3 vowels) can be chosen in (`""^4C_2xx""^5C_1)+""^4C_3` ways

Hence, required probability = `((""^4C_2xx""^5C_1)+""^4C_3)/(""^9C_3)=17/42`