Advertisements
Advertisements
प्रश्न
A = {x : 11x – 5 > 7x + 3, x ∈R} and B = {x : 18x – 9 ≥ 15 + 12x, x ∈R}. Find the range of set A ∩ B and represent it on a number line
उत्तर
A = {x : 11x – 5 > 7x + 3, x ∈R}
B = {x : 18x – 9 ≥ 15 + 12x, x ∈R}
Now, A = 11x – 5 > 7x + 3
⇒ 11x – 7x > 3 + 5
⇒ 4x > 8
⇒ x > 2, x ∈ R
B = 18x - 9 ≥ 15 + 12x
⇒ 18x - 12x ≥ 15 + 9
⇒ 6x ≥ 24
⇒ x ≥ 4
∴ A ∩ B = x ≥ 4, x ∈ R
Hence Range of A ∩ B = {x : x ≥ 4, x ∈ R} and its graph will be.
APPEARS IN
संबंधित प्रश्न
Solve the following inequation and write the solution set:
13x – 5 < 15x + 4 < 7x + 12, x ∈ R
Represent the solution on a real number line.
Find the values of x, which satisfy the inequation `-2 5/6 < 1/2 - (2x)/3 ≤ 2, x ∈ W`. Graph the solution set on the number line.
Represent the solution of the following inequalities on the real number line:
7 – x ≤ 2 – 6x
Solve the following linear in-equation and graph the solution set on a real number line:
`5/4 "x" > 1 + 1/3 (4"x" - 1)` , x ∈ R
Solve the following inequalities and represent the solution on a number line:
2x - 3 > 5x + 4
Solve the following inequalities and represent the solution set on a number line:
`0 < (3x - 2)/(4) ≤ 2`
Solve : `(4x - 10)/(3) ≤ (5x - 7)/(2)` x ∈ R and represent the solution set on the number line.
Solve the inequation – 3 ≤ 3 – 2x < 9, x ∈ R. Represent your solution on a number line.
If x ∈ R (real numbers) and – 1 < 3 – 2x ≤ 7, find solution set and represent it on a number line.
For the replacement set = {– 8, – 6, – 4, – 2, 0, 2, 4, 6, 8}, which of the following is not a solution set?
