Question

Alkyl chloride containing 4° carbon atom(s) would be ____________.

पर्याय

• tert-butyl chloride

• neopentyl chloride

• sec-butyl chloride

• n-propyl chloride

Answer 1

Alkyl chloride containing 4° carbon atom(s) would be neopentyl chloride.

Explanation:

1. \[\begin{array}{cc}
\phantom{....}\ce{\overset{1°}{C}H3}\phantom{}\\
\phantom{..}|\\
\ce{\overset{1°}{C}H3 - \overset{3°}{C} - Cl}\\
\phantom{..}|\\
\phantom{....}\ce{\underset{tert-Butyl chloride}{\overset{1°}{C}H3}}
\end{array}\]

2. \[\begin{array}{cc}
\ce{\overset{1°}{C}H3}\phantom{..}\\
|\phantom{.....}\\
\ce{\overset{1°}{C}H3 - \overset{4°}{C} - \overset{1°}{C}H2 - Cl}\\
|\phantom{.....}\\
\ce{\underset{Neopentyl chloride}{\overset{1°}{C}H3}}\phantom{..}
\end{array}\]

3. \[\begin{array}{cc}
\ce{\overset{1°}{C}H3 - \overset{2°}{C}H2 - \overset{2°}{C}H - \overset{1°}{C}H3}\\
\phantom{.....}|\\
\phantom{......}\ce{\underset{sec-Butyl chloride}{Cl}}
\end{array}\]

4. \[\begin{array}{cc}
\ce{\overset{1°}{C}H3 - \overset{2°}{C}H2 - \overset{1°}{C}H2}\\
\phantom{...........}|\\
\phantom{.............}\ce{\underset{{n}-Propyl chloride}{Cl}}
\end{array}\]