Question

Among two supplementary angles, the measure of the larger angle is 44^o more than the measure of the smaller. Find their measures.

Answer 1

Let the measure of larger angle be x° and the measure of smaller angle be y°.

Among two supplementary angles, the measure of the larger angle is 44° more than the measure of the smaller.

According to condition,

x = y + 44° 

x + y = 180°

⇒ (y + 44°) + y = 180°

⇒ y + 44° + y = 180°

⇒ 2y + 44° = 180°

⇒ 2y = 180° - 44°

⇒ 2y = 136°

⇒ y = `(136°)/2`

⇒ y = 68°.

∴ x = y + 44° 

x = 68° + 44° 

x = 112°