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प्रश्न
An ac source V = 282 sin (100 t) volt is connected across a 1 μF capacitor. The rms value of current in the circuit will be ______.
(take √2 = 1.41)
पर्याय
10 mA
20 mA
40 mA
80 mA
MCQ
रिकाम्या जागा भरा
उत्तर
An ac source V = 282 sin (100 t) volt is connected across a 1 μF capacitor. The rms value of current in the circuit will be 20 mA.
Explanation:
Given, V = 282 sin(100t) V
C = 1 µF = 10−6 F
Pue capacitive, `X_c = 1/(omegaC) = 1/(100 xx 10^-6)`
= 104 Ω
`I_0 = V_0/X_C = 282/10^4 = 28.2 mA`
`I_(rms) = I_0/sqrt2 = 28.2/sqrt2`
Irms = 20 mA
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