मराठी

An ac source V = 282 sin (100 t) volt is connected across a 1 μF capacitor. The rms value of current in the circuit will be ______.(take √2 = 1.41) - Physics

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प्रश्न

An ac source V = 282 sin (100 t) volt is connected across a 1 μF capacitor. The rms value of current in the circuit will be ______.
(take √2 = 1.41)

पर्याय

  • 10 mA

  • 20 mA

  • 40 mA

  • 80 mA

MCQ
रिकाम्या जागा भरा

उत्तर

An ac source V = 282 sin (100 t) volt is connected across a 1 μF capacitor. The rms value of current in the circuit will be 20 mA.

Explanation:

Given, V = 282 sin(100t) V

C = 1 µF = 10−6 F

Pue capacitive, `X_c = 1/(omegaC) = 1/(100 xx 10^-6)`

= 104 Ω

`I_0 = V_0/X_C = 282/10^4 = 28.2 mA`

`I_(rms) = I_0/sqrt2 = 28.2/sqrt2`

Irms = 20 mA

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