Question

An electron of mass m_e, and a proton of mass m_p = 1836 m_e are moving with the same speed. The ratio of the de Broglie wavelength `lambda_"electron"/lambda_"proton"` will be:

पर्याय

• `1/1836`

• 918

• 1

• 1836

Answer 1

1836

Explanation:

de-Broglie wavelength, λ = `"h"/"p"`

`lambda_"e"="h"/("m"_"e"xx"v")` and `lambda_"p"="h"/("m"_"p"xx"v")`

∴ `lambda_"e"/lambda_"p" = "m"_"p"/"m"_"e"`

= `(1836"m"_"e")/"m"_"e"`

= 1836.