Advertisements
Advertisements
प्रश्न
An element X has the following isotopic composition 200X = 90%, 199X = 8% and 202X = 2%. The weighted average atomic mass of the element X is closest to
पर्याय
201 u
202 u
199 u
200 u
उत्तर
200 u
Explanation:
X = `((200 xx 90) + (199xx 8) + (202 xx 2))/100`
= 199.96
= 200 u
APPEARS IN
संबंधित प्रश्न
Calculate the molecular mass of the following in u.
CH3COOH
Calculate the molecular mass of the following in u.
C2H5OH
Solve problem:
The mass of an atom of hydrogen is 1.008 u. What is the mass of 18 atoms of hydrogen?
Solve problem:
Calculate the number of atoms of the following. (Average atomic mass : N = 14 u, S = 32 u)
1.6 g of sulfur
Calculate the number of atoms of hydrogen present in 5.6 g of urea, \[\ce{(NH2)2CO}\]. Also calculate the number of atoms of N, C, and O.
Explain formula mass with an example.
Which one of the following is used as a standard for atomic mass.
Boron has two isotopes 10B and 11B with atomic masses 10 and 11, respectively. If its average atomic mass is 10.81, the abundance of 10B is ____________.
What is the average mass of an element if it has two isotopes, one of mass 6.015 u with 8.24 % and other of mass 7.016 u with 91.26% respectively?
The unit of atomic mass, amu is replaced by u, here u stands for ______.
