Question

An equilibrium system for the reaction between hydrogen and iodine to give hydrogen iodide at 765 K in a 5 litre volume contains 0.4 mole of hydrogen, 0.4 mole of iodine and 2.4 moles of hydrogen iodide.

\[\ce{H2 + I2 <=> 2HI}\]

The equilibrium constant for the reaction is:

पर्याय

• 36.0

• 15.0

• 0.067

• 0.028

Answer 1

36.0

Explanation:

	\[\ce{H2}\]	\[\ce{+}\]	\[\ce{I2}\]	\[\ce{<=>}\]	\[\ce{2HI}\]
At equ.	`0.4/5`		`0.4/5`		`2.4/5`

Kc = `(2.4/5)^2/((0.4/5)(0.4/5))`

K_c = `(2.4 xx 2.4)/(0.4 xx 0.4)`

K_c = `5.76/0.16`

K_c = 36