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प्रश्न
An erect image 2.0 cm high is formed 12 cm from a lens, the object being 0.5 cm high. Find the focal length of the lens.
उत्तर
Given:
Image distance, v =-12 cm (Image is erect.)
Height of the object, h = 0.5 cm
Height of the image, h' = 2.0 cm
Applying magnification formula, we get:
m = v/u = h'/h
-12/u = 2.0/0.5
or, object distance, u =-3 cm
Applying lens formula, we get:
1/v- 1/u = 1/f
1/(-12)-1/(-3) = 1/f
or, 1/f = 3/12
or, focal length, f = 4.0 cm
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