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प्रश्न
An expansion process on a diatomic ideal gas (Cv = 5/2 R), has a linear path between the initial and final coordinates on a pV diagram. The coordinates of the initial state are: the pressure is 300 kPa, the volume is 0.08 m3 and the temperature is 390 K. The final pressure is 90 kPa and the final temperature s 320 K. The change in the internal energy of the gas, in SI units, is closest to:
पर्याय
-11,000
-6500
11,000
zero
MCQ
उत्तर
-11,000
Explanation:
ΔU = nCv ΔT
= n `5/2`R (Tf - Ti)
n = `("P"_1"V"_1)/("RT"_1)`
ΔU = `("P"_1"V"_1)/("RT"_1)xx5/2` R (T2 - T1)
= `(300xx10^3xx0.08)/390xx5/2(320-390)`
= `(15xx10^3xx0.08xx5)/39xx(-70)`
= `-0.40/39xx15xx10^3xx70`
= `-40/39xx150xx70`
= `-40/39xx10500`
ΔU = -11000 Joule
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