Question

An iron rod is placed parallel to magnetic field of intensity 2000 Am^-1. The magnetic flux through the rod is 6 × 10⁻⁴ Wb and its cross-sectional area is 3 cm². The magnetic permeability of the rod in Wb A^-1m^-1 is ______.

पर्याय

• 10^-1

• 10^-2

• 10^-3

• 10^-4

Answer 1

An iron rod is placed parallel to magnetic field of intensity 2000 Am^-1. The magnetic flux through the rod is 6 × 10⁻⁴ Wb and its cross-sectional area is 3 cm². The magnetic permeability of the rod in Wb A^-1m^-1 is 10^-3.

Explanation:

Given, B₀ = magnetic field after insertion of iron rod - 2000 Am^-1

Magnetic flux, Φ = 6 × 10⁻⁴ Wb

Area of cross-section, A = 3 cm² = 3 × 10⁻⁴ m magnetic permeability of the rod,

μ_r = `"B"/"B"_0=phi/("A"xx"B"_0)`   [∵ Φ = BA]

So, μ_r = `"B"/(2000"Am"^-1)` 

∴ μ_r = `(6xx10^-4"Wb")/(3xx10^-4"m"^2)xx1/(2000"Am"^-1)`

= 10^-3 Wb A^-1m^-1