Question

An iron rod is placed parallel to magnetic field of intensity 4000 A/m. The magnetic flux through the rod is 8 x 10^-4 Wb and its cross-sectional area is 4 cm² . The magnetic permeability of the rod in Wb/A - m is ____________.

पर्याय

• 5 x 10^-1

• 5 x 10^-2

• 5 x 10^-4

• 5 x 10^-6

Answer 1

An iron rod is placed parallel to magnetic field of intensity 4000 A/m. The magnetic flux through the rod is 8 x 10^-4 Wb and its crosssectional area is 4 cm² . The magnetic permeability of the rod in Wb/A - m is 5 x 10^-4.

Explanation:

`mu = "B"/"H" = (phi//"A")/"H" = phi/("HA") = (8 xx 10^-4)/(4000 xx 4 xx 10^-4)`

`therefore  mu = 5 xx 10^-4  "Wb"//"A-m"`