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प्रश्न
An object at an angle such that the horizontal range is 4 times the maximum height. What is the angle of projection of the object?
उत्तर
Given,
Horizontal range = 4Hmax
Solution:
Horizontal range = `(u^2 sin2theta)/g = (2u^2 sintheta costheta)/g`
Maximum height = `(u^2 sin^2theta)/(2g)`
as given `(2u^2 sin theta costheta)/g = (4u^2 sin^2theta)/(2g)`
2 cosθ = 2 sinθ
tanθ = 1
∴ θ = 45°
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