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प्रश्न
An object is placed at a distance 24 cm in front of a convex lens of focal length 8 cm.
(i) What is the nature of the image so formed?
(ii) Calculate the distance of the image from the lens.
(iii) Calculate the magnification of the image.
उत्तर
(i) As for convex lens, if |u| > | f | then real and inverted image is formed and as |u| > 2| f | then it is diminished.
(ii) `1/v - 1/u = 1 /f`
`1/v = 1/u + 1 /f`
`1/v = (f+u)/(uf)`
`⇒ v =(uf)/(f+u)`
= `((-24)(8))/((8)+(-24))`
= `(-24xx8)/(-16)`
= `(-192)/-16`
= 12 cm
(iii) m = `v/u = 12/-24 = -0.5`
The negative sign signifies an inverted image.
संबंधित प्रश्न
Where must the object be placed for the image formed by a converging lens to be:
real, inverted and larger than the object?
An illuminated object is placed at a distance of 20 cm from a converging lens of focal length 15 cm. The image obtained on the screen is:
(a) upright and magnified
(b) inverted and magnified
(c) inverted and diminished
(d) upright and diminished
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a converging lens, and which is
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