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प्रश्न
Are the following pair of linear equations consistent? Justify your answer.
x + 3y = 11, 2(2x + 6y) = 22
बेरीज
उत्तर
Conditions for pair of linear equations to be consistent are:
`a_1/a_2 ≠ b_1/b_2` ......[Unique solution]
`a_1/a_2 = b_1/b_2 = c_1/c_2` ......[Coincident or infinitely many solutions]
No.
The given pair of linear equations
x + 3y = 11 and 2x + 6y = 11
Comparing the above equations with ax + by + c = 0
We get,
a1 = 1, b1 = 3, c1 = 11
a2 = 2, b2 = 6, c2 = 11
`a_1/a_2 = 1/2`
`b_1/b_2 = 1/2`
`c_1/c_2` = 1
Here, `a_1/a_2 = b_1/b_2 ≠ c_1/c_2`
Hence, the given pair of linear equations has no solution.
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