Question

Area in first quadrant bounded by y = 4x², x = 0, y = 1 and y = 4 is ______.

पर्याय

• `3/7`

• `5/7`

• `7/3`

• `7/5`

Answer 1

Area in first quadrant bounded by y = 4x², x = 0, y = 1 and y = 4 is `underlinebb(7/3)`.

Explanation:

A = `1/2int_1^4 sqrt(y)dy`

= `1/3[y^(3/2)]_1^4`

= `7/3`