Advertisements
Advertisements
प्रश्न
Assertion (A): The ionisation of hydrogen sulphide in water is low in the presence of hydrochloric acid.
Reason (R): Hydrogen sulphide is a weak acid.
पर्याय
Both A and R are true and R is correct explanation of A.
Both A and R are true but R is not correct explanation of A.
A is true but R is false.
Both A and R are false.
उत्तर
Both A and R are true but R is not correct explanation of A.
Explanation:
In presence of \[\ce{H+}\] ion, equilibrium shifts in backward direction.
APPEARS IN
संबंधित प्रश्न
The ionization constant of HF, HCOOH and HCN at 298K are 6.8 × 10–4, 1.8 × 10–4 and 4.8 × 10–9 respectively. Calculate the ionization constants of the corresponding conjugate base.
The ionization constant of phenol is 1.0 × 10–10. What is the concentration of phenolate ion in 0.05 M solution of phenol? What will be its degree of ionization if the solution is also 0.01M in sodium phenolate?
The ionization constant of acetic acid is 1.74 × 10–5. Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ion in the solution and its pH.
The ionization constant of chloroacetic acid is 1.35 × 10–3. What will be the pH of 0.1M acid and its 0.1M sodium salt solution?
\[\ce{K_{a_1}, K_{a_2}}\] and \[\ce{K_{a_3}}\] are the respective ionisation constants for the following reactions.
\[\ce{H2S ⇌ H^{+} + Hs-}\]
\[\ce{Hs- ⇌ H^{+} + S^{2-}}\]
\[\ce{H2S ⇌ 2H^{+} + S^{2-}}\]
The correct relationship between \[\ce{K_{a_1}, K_{a_2}}\] and \[\ce{K_{a_3}}\] is ______.
What will be the value of pH of 0.01 mol dm–3 \[\ce{CH3COOH}\] (Ka = 1.74 × 10–5)?
According to the Ostwald's dilution law, for a weak electrolyte, the degree of ionization is ______.
