Advertisements
Advertisements
प्रश्न
At the given point of time, the earth receives energy from the sun at 4 cal cm–2 min–1. Determine the number of photons received on the surface of the Earth per cm2 per minute. (Given: Mean wavelength of sunlight = 5500 Å)
उत्तर
E = 4 calorie = 4 × 4.184 J
λ = 5500 Å
Number of photons received on the surface of the earth, from E = nhv
n = `("E"λ)/"hc"`
= `(4 xx 4.184 xx 5500 xx 10^-10)/(6.6 xx 10^-34 xx 3 xx 10^8)`
= `(9.2048 xx 10^-10)/(19.8 xx 10^-26)`
= 4648 × 1016
= 4.648 × 1019
n = 4.65 × 1019
APPEARS IN
संबंधित प्रश्न
When a metallic surface is illuminated with radiation of wavelength λ, the stopping potential is V. If the same surface is illuminated with radiation of wavelength 2λ, the stopping potential is `"V"/4`. The threshold wavelength for the metallic surface is
In photoelectric emission, a radiation whose frequency is 4 times threshold frequency of a certain metal is incident on the metal. Then the maximum possible velocity of the emitted electron will be
How does photocurrent vary with the intensity of the incident light?
What is a photocell?
Define stopping potential.
List out the laws of photoelectric effect.
Explain experimentally observed facts of the photoelectric effect with the help of Einstein’s explanation.
List out the characteristics of photons.
How many photons per second emanate from a 50 mW laser of 640 nm?
A 3310 Å photon liberates an electron from a material with energy 3 × 10−19 J while another 5000 Å photon ejects an electron with energy 0.972 × 10−19 J from the same material. Determine the value of Planck’s constant and the threshold wavelength of the material.