Question

अवयव पाडा.

`y^3+1/(8y^3)`

Answer 1

माहीत आहे की,

a³ + b³ = (a + b)(a² – ab + b²)

`y^3+1/(8y^3)`

येथे, a = y आणि b = `1/2y`

`y^3 + 1/(8y^3) = (y + 1/(2y))[y^2 - y(1/(2y)) + (1/(2y))^2]`

`(y + 1/(2y))(y^2 1/2 + 1/(4y^2))`