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प्रश्न
Balance the following equation by the ion electron method.
\[\ce{KMnO4 + SnCl2 + HCl -> MnCl2 + SnCl4 + H2O + KCl}\]
उत्तर
\[\ce{M^{+7}nO^-_4 -> Mn^2+}\] ........(1)
and \[\ce{Sn^2+ -> Sn^4+}\] ........(2)
\[\ce{MnO^-_4 + 8H^+ + 5e^- -> Mn^2+ + 4H2O}\] ....[Eq. (1)]
\[\ce{Sn^2+ -> Sn^4+ + 2e^-}\] .........[Eq. (2)]
\[\ce{2MnO^-_4 + 16H^+ + 10e^- -> 2Mn^2+ + 8H2O}\] .......[(1) × 2]
\[\ce{5Sn^2+ -> 5Sn^4+ + 10e^-}\] ......[(2) × 5]
\[\ce{2MnO^-_4 + 5Sn^2+ + 16^H+ -> 2Mn^2+ + 5Sn^4+ + 8H2O}\]
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