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प्रश्न
By using Regular falsi method solve 2x – 3sin x – 5 = 0.
बेरीज
उत्तर
Let f(x) = 2x – 3sin x - 5
f(1) = -5
f(2) = -5.5244
f(3) = -3.7379 < 0
f(4) = 0.5766 > 0
∴ Roots lies between 2 and 3
| Iteration | a | b | f(a) | f(b) | x=`(af(b)-bf(a))/(f(b)-f(a))` | f(x) |
| I. | 2 | 3 | -3.7279 | 0.5766 | 2.8660 | -0.0841 |
| II. | 2.866 | 3 | -0.0841 | 0.5766 | 2.8831 | -0.0009 |
| III. | 2.8831 | 3 | 0.0009 | 0.5766 | 2.8833 | - |
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Regula – Falsi Equation
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