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प्रश्न
Calculate coefficient of variation from the following data:
Income (in Rs): | 1000-1700 | 1700-2400 | 2400-3100 | 3100-3800 | 3800-4500 | 4500-5200 |
No. of families: | 12 | 18 | 20 | 25 | 35 | 10 |
उत्तर
Income (Rs) |
\[f_i\]
|
Midpoint
\[\left( x_i \right)\]
|
\[u_i = \frac{x_i - 3450}{700}\]
|
\[f_i u_i\]
|
\[f_i {u_i}^2\]
|
1000−1700 | 12 | 1350 | −3 | −36 | 108 |
1700−2400 | 18 | 2050 | −2 | −36 | 72 |
2400−3100 | 20 | 2750 | −1 | −20 | 20 |
3100−3800 | 25 | 3450 | 0 | 0 | 0 |
3800−4500 | 35 | 4150 | 1 | 35 | 35 |
4500−5200 | 10 | 4850 | 2 | 20 | 40 |
\[\sum f_i = 120\]
|
\[\sum f_i u_i= 37\]
|
\[\sum f_i {u_i}^2 = 275\]
|
\[\bar{X} = a + h\left( \frac{\sum f_i u_i}{N} \right) = 3450 + 700\left( \frac{- 37}{120} \right) = 3234 . 17\]
\[\sigma^2 = h^2 \left[ \frac{\sum f_i {u_i}^2}{N} - \left( \frac{\sum f_i u_i}{N} \right)^2 \right] = 490000\left[ \frac{275}{120} - \frac{1369}{14400} \right] = 1076332 . 64\]
\[\sigma = \sqrt{1076332 . 64} = 1037 . 46\]
\[CV = \frac{\sigma}{\bar{X}} \times 100 = \frac{1037 . 46}{3234 . 17} \times 100 = 32 . 08\]
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Find the mean, mode, S.D. and coefficient of skewness for the following data:
Year render: | 10 | 20 | 30 | 40 | 50 | 60 |
No. of persons (cumulative): | 15 | 32 | 51 | 78 | 97 | 109 |
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Firm A | Firm B | |
No. of wage earners | 586 | 648 |
Average weekly wages | Rs 52.5 | Rs. 47.5 |
Variance of the |
100 |
121 |
distribution of wages |
(i) Which firm A or B pays out larger amount as weekly wages?
(ii) Which firm A or B has greater variability in individual wages?
The following are some particulars of the distribution of weights of boys and girls in a class:
Number | Boys | Girls |
100 | 50 | |
Mean weight | 60 kg | 45 kg |
Variance | 9 | 4 |
Which of the distributions is more variable?