Question

Calculate half-life of a first order reaction in minute if the rate constant is 1 × 10^-3 s^-1.

पर्याय

• 15

• 6.93

• 11.55

• 9.3

Answer 1

11.55

Explanation:

Using the formula of half-life of a first order reaction,

`"t"_(1//2) = 0.693/"K"`

Converting K into min^-1,

K = `1 xx 10^-3 "s"^-1`

`= 60 xx 1 xx 10^-3 "min"^-1`

= 0.06 min^-1

So, `"t"_(1//2) = 0.693/0.06 = 11.55` min