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प्रश्न
Calculate half-life period of life order reaction whose rate constant is 200 sec–1
पर्याय
4.265 × 10–3 sec.
3.465 × 10–3 sec.
2.562 × 10–2 sec.
2.111 × 10–2 sec.
MCQ
उत्तर
3.465 × 10–3 sec.
Explanation:
Half-life period `t_(1/2) = 0.693/K`
`0.693/(200 sec^-1)` = 3.465 × 10–3 sec
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