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प्रश्न
Calculate the quantity of heat produced in a 20 Ω resistor carrying 2.5 A current in 5 minutes.
उत्तर
Given : R = 20Ω, I = 2.5 A
t = 5 minutes = 5 x 60 = 300 s
Quantity of heat produced is given as
H = I2Rt
= (2.5)2 x 20 x 300
∴ H = 37500 J
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संबंधित प्रश्न
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| Potential differences, V (in volts) | : | 2.5 | 5.0 | 10.0 | 15.0 | 20.0 | 25.0 |
| Current, I (in amperes) | : | 0.1 | 0.2 | 0.4 | 0.6 | 0.8 | 1.0 |
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