मराठी

Calculate the quantity of the pure lime and soda required for softening of 1,00,000 litres of water containing the following impurities in ppm. - Applied Chemistry 1

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प्रश्न

Calculate the quantity of the pure lime and soda required for softening of 1,00,000 litres of water containing the following impurities in ppm. The purity of lime is 70% and soda is BS% Ca(HCO3) = 30.2 , Mg(HCO3) = 20.8 ,CaCI2 = 28.1 ,MgCl2 = 8.78, CaSO= 35, MgSO4 = 6.7 .

थोडक्यात उत्तर

उत्तर

 

impurities( mg/lit) Multification fector CaC03 equivalent Mg/lif Requirement
Ca(Hco3)=30.2 `100/162` `30.2 xx 100/162 = 18.64` L
Mg(Hco3) =20.8 `100/146` `20.8 xx 100/146 = 14.24`  2L
CaCl2 = 28.1  `100/111` `28.1 xx 100/111=25.32` S
CaS04=35 `100/136` `35 xx 100/136 = 25.74` S
MgS04 = 6.7  `100/120` `6.7xx 100/120=5.58` L+S
MgCl2 = 8.7 `100/95` `8.7 xx 100/95 = 9.16` L+S

`"Lime" =74/100 [CaCO_3  "equivalent of"  Ca (HCO_3)+ 2 xx Mg (HCO_3) + MgCI_2 xx MgSO_4 ]xx ("Volume of water")/(1000) xx 100/(%"Purity").`

`=74/100 [18.64 + 2 xx 14.25 + 9.16 + 5.58] xx (100000)/1000 xx 100/70.`

= 6541.6 gms

`"Soda" = 106/100 [CaCO_3  "equivalent of " MgCI_2 + MgSO_4 + CaSO_4 ] xx "Volum of water "/1000 xx 100/(%"Purity")`

`= 106/100 [25.31 + 9.16 +25.73 + 5.58 ] xx (100000)/1000 xx 100/85`.

= 8203 .15gms.

The lime requirement is 6541.6 gms and soda requirement is 8203. 15 gms.

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Softening of water by Hot and Cold lime Soda method and numerical problems
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