Question

Calculate Δ_subH of the H₂O from the given data:
\[\ce{H2O_{(s)}->H2O_{(l)},}\] Δ_fusH = 6.01kJ mol⁻¹

\[\ce{H2O_{(l)}-> H2O_{(g)},}\] Δ_VapH = 45.07 kJ mol⁻¹.

Answer 1

Given:

\[\ce{H2O_{(s)}->H2O_{(l)}}\] 

\[\ce{H2O_{(l)}-> H2O_{(g)}}\]

Δ_subH = ?

\[\ce{H2O_{(s)}->H2O_{(l)}}\] 

+ \[\ce{H2O_{(l)}-> H2O_{(g)}}\]
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\[\ce{H2O_{(s)} + H2O_{(l)}-> H2O_{(l)} + H2O_{(g)}}\] 

\[\ce{H2O_{(s)}->H2O_{(g)}}\]

Δ_subH = Δ_fusH + Δ_VapH

= 6.01kJ mol⁻¹ + 45.07 kJ mol⁻¹

∴ Δ_subH = 51.08 kJ mol⁻¹