Question

Calculate the atom economy of the following:

(At mass of C = 12, H = 1, 0 = 16)

$$\mathrm{CH}{\phantom{A}}_3-\mathrm{CH}{\phantom{A}}_2-\mathrm{OH}\stackrel{\mathrm{\Delta }}{\to }\mathrm{CH}{\phantom{A}}_2=\mathrm{CH}{\phantom{A}}_2+\mathrm{H}{\phantom{A}}_2\mathrm{O}$$

Answer 1

${\displaystyle \text{Atom economy}=\frac{\text{Formula weight of desired product}}{\text{Sum of formula weight of all the reactants used in the reaction}}\times 100}$

Formula weight of ethanol = 46

ethene = 28

water = 18

${\displaystyle \% \text{atom economy}=\frac{28}{46}\times 100=60.9\%}$