Advertisements
Advertisements
प्रश्न
Calculate the compound interest for the second year on ₹ 8,000/- invested for 3 years at 10% per annum.
उत्तर
For 1st year
P = ₹8000
R = 10%
T = 1 year
I = `[8000 xx 10 xx 1]/100` = 800
A = ₹8000 + ₹800 = ₹8800
For 2nd year
P = ₹8800
R = 10%
T = 1 year
I = `[ 8800 xx 10 xx 1]/100`
Compound interest for 2nd years = ₹880
Amount after 2 years = ₹8800 + ₹880 = ₹9680.
Principal for the third year = ₹9680.
Interest for the third year = `₹(9680 × 10 × 1)/100` = ₹968.
Amount after 3 years = ₹9680 + ₹968 = ₹10648.
Hence, the compound interest for the second year on ₹8000 invested for 3 years at 10% p.a. is ₹880, and the sum due at the end of the third year is ₹10648.
APPEARS IN
संबंधित प्रश्न
If a, b, c are in continued proportion, prove that (a + b + c) (a – b + c) = a2 + b2 + c2
Mr Kumar borrowed Rs. 15000 for two years. The rates of interest for two successive years are 8% and 10% respectively. If he repays Rs. 6200 at the end of the first year, find the outstanding amount at the end of the second year.
Calculate the amount and the compound interest for the following:
Rs. 7500 at 12% p.a. in 3 years.
A sum of Rs. 65000 is invested for 3 years at 8 % p.a. compound interest.
Find the sum due at the end of the first year.
Alisha invested Rs 75000 for 4 years at 8 % p.a. compound interest,
Calculate the interest for the fourth year.
Aryan borrowed a sum or Rs. 36,000 for `1 1/2` years at 10 % p.a. compound interest.
Find the amount he needs to return to clear the debt.
Natasha gave Rs.6O,OOO to Nimish for 3 years at 15%,p.a. compound interest.
Calculate to the nearest rupee :
The amount Natasha receives at the end of 3 years.
Calculate the amount and the compound interest on :
Rs. 6,000 in 3 years at 5% per year.
Calculate the amount and the compound interest on:
Rs. 8,000 in `2 1/2` years at 15% per year.
Govind borrows Rs 18,000 at 10% simple interest. He immediately invests the money borrowed at 10% compound interest compounded half-yearly. How much money does Govind gain in one year?
