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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Calculate the longest wavelength in the Paschen series. (Given RH =1.097 ×107 m-1) - Physics

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प्रश्न

Calculate the longest wavelength in the Paschen series.

(Given RH =1.097 ×107 m-1)  

बेरीज

उत्तर

Given: n = 3, m = 4

To find: Longest wavelength in Paschen series (λL)

Formula: `1/lambda_"L" = "R"[1/"n"^2 - 1/"m"^2]`

Calculation: 

From formula,

`1/lambda_"L" = "R"[1/3^2 - 1/4^2]`

∴ `1/lambda_"L" = "R"[1/9 - 1/16]`

= `"R"[(16 - 9)/(9 xx 16)] = (1.097 xx 10^7 xx 7)/(9 xx 16)`

∴ `lambda_"L" = (9 xx 16)/(1.097 xx 7) xx 10^-7`

= antilog {log(9) + log(16) − log(1.097) − log(7)} × 10−7

= antilog{0.9542 + 1.2041 − 0.0402 − 0.8451} × 10−7 

= antilog{1.2730} × 10−7

= 18.75 × 10−7 m

∴ λL = 18750 Å

The longest wavelength in the Paschen series is 18750 Å. 

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Bohr’s Atomic Model
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