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प्रश्न
Calculate the mass of iron in 10 kg of iron ore which contains 80% of pure ferric oxide.
उत्तर
In Fe2O3 , Fe = 56 and O = 16
Molecular mass of Fe2O3 = 2 × 56 + 3 ×16 = 160 g
Iron present in 80% of Fe2O3 = `112/160 xx 80 = 56`g
So, mass of iron in 100 g of ore = 56 g
mass of Fe in 10000 g of ore = `56 xx 10000/100`
= 5.6 kg
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