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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride. - Chemistry

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प्रश्न

Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.

संख्यात्मक

उत्तर

Let the total mass of the solution be 100 g, and the mass of benzene be 30 g.

∴ Mass of carbon tetrachloride = (100 − 30) g

= 70 g

Molar mass of benzene (C6H6) = (6 × 12 + 6 × 1) g mol−1

= 78 g mol−1

∴ Number of moles of C6H6 = `"Mass"/"Molar mass"`

= `(30  "g")/(78  "g mol"^(−1))`

= 0.385 mol

Molar mass of carbon tetrachloride (CCl4) = 1 × 12 + 4 × 35.5

= 154 g mol−1

∴ Number of moles of CCl4 = `"Mass"/"Molar mass"`

= `(70  "g")/(154  "g mol"^(−1))`

= 0.455 mol

Thus, the mole fraction of C6H6 is given as:

`("Number of moles of C"_6"H"_6)/("Number of moles of C"_6"H"_6+"Number of moles of CCl"_4)`

= `0.385/(0.385+0.455)`

= 0.458

∴ Mole fraction of CCl4 = 1 − 0.458 = 0.542

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पाठ 2: Solutions - Intext Questions [पृष्ठ ३७]

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एनसीईआरटी Chemistry [English] Class 12
पाठ 2 Solutions
Intext Questions | Q 2 | पृष्ठ ३७

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