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Calculate the momentum of the electrons accelerated through a potential difference of 56 V. - Physics

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प्रश्न

Calculate the momentum of the electrons accelerated through a potential difference of 56 V.

संख्यात्मक

उत्तर

Potential difference, V = 56 V

Planck’s constant, h = 6.6 × 10−34 Js

Mass of an electron, m = 9.1 × 10−31 kg

Charge on an electron, e = 1.6 × 10−19 C

At equilibrium, the kinetic energy of each electron is equal to the accelerating potential, i.e., we can write the relation for velocity (v) of each electron as:

`1/2 "mv"^2 = "eV"`

`"v"^2 = (2"eV")/"m"`

∴ v = `sqrt((2xx1.6xx10^(-19) xx 56)/(9.1 xx 10^(-31)))`

= `sqrt(19.69 xx 10^12)`

= 4.44 × 106 m/s

The momentum of each accelerated electron is given as:

p = mv

= 9.1 × 10−31 × 4.44 × 106

= 4.04 × 10−24 kg m s−1

Therefore, the momentum of each electron is 4.04 × 10−24 kg m s−1.

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पाठ 11: Dual Nature of Radiation and Matter - Exercise [पृष्ठ ४०८]

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एनसीईआरटी Physics [English] Class 12
पाठ 11 Dual Nature of Radiation and Matter
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एनसीईआरटी Physics [English] Class 12
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