Question

Calculate the potential of hydrogen electrode at 25°C:

Pt, H₂ (1 atm) | H⁺ (0.1 M)

पर्याय

• 0.0592 V

• −0.0592 V

• −0.1184 V

• +0.1184 V

Answer 1

0.0592 V

Explanation:

E = `"E"^0 - 0.0592/2 log_10  (["H"^+]^2)/("P"_("H"_2)`

= `0 - 0.0592/2 log_10  (0.1)^2/1`

= `-0.0592/2 xx (-2)`

= 0.0592 V