Given: F = 300 N; `"A" = 30 " cm"^2 = 30/(100xx100)"m" ^2 = 30xx10^-4 "m"^2`
To Find: Pressure
`therefore "P" = "F"/"A"`
`= 300/(30/(100xx100)`
` = (300xx100xx100)/30`
= 100000
= 105 Pa
Calculate the pressure in pascal exerted by a force of 300 N acting normally on an area of 30 cm2.
Given: F = 300 N; `"A" = 30 " cm"^2 = 30/(100xx100)"m" ^2 = 30xx10^-4 "m"^2`
To Find: Pressure
`therefore "P" = "F"/"A"`
`= 300/(30/(100xx100)`
` = (300xx100xx100)/30`
= 100000
= 105 Pa
The unit of pressure is .........
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2. | 1 gwt | Milk |
3. | Pascal’s law | `"Mass"/" Volume"` |
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(A) | (B) | (C) |
The total force exerted by a body normal to the surface is called ______.