Question

Calculate the value `"E"_"cell"^circ` at 298 K for the following cell. 

\[\ce{Al | Al^{3+} (0.01 M) || Sn^{2+} (0.015 M) | Sn}\]

`"E"_("Al"^(3+)//"Al")^circ` = - 1.66 V and `"E"_("Sn"^(2+)//"Sn")^circ` = - 0.14 V

पर्याय

• 1.50 V

• 1.51 V

• 1.52 V

• 1.53 V

Answer 1

1.52 V

Explanation:

The value of E° is calculated by the formula,

`"E"_"cell"^circ = "E"_"cathode"^circ - "E"_"anode"^circ`

or

`"E"_"cell"^circ = "E"_"oxidation"^circ - "E"_"reduction"^circ`      ...[\[\ce{2Al + 3Sn^{2+} -> 2Al^{3+} + 3Sn}\]]

`"E"_"cell"^circ` = - 0.14 - (- 1.66)

`"E"_"cell"^circ` = - 0.14 + 1.66

`"E"_"cell"^circ` = 1.52 V