Advertisements
Advertisements
प्रश्न
Calculate the wavelength associated with an electron, its momentum and speed when it is moving with the kinetic energy of 150 eV.
उत्तर
Data: V = 54 V, m = 9.1 x 10-31 kg,
e = 1.6 x 10-19C, h = 6.63 x 10-34 J.s, KE = 150 eV
As KE ∝ `sqrt"V"`, we get
`"v'"/"v" = sqrt(150/54)` = 1.666
∴ v' = 1.666 v = (1.666)(4.359 × 106)
= 7.262 × 106 m/s
This is the speed of the electron.
p' = mv' = (9.1 × 10-31)(7.262 × 106)
= 6.608 × 10-24 kg.m/s
`lambda' = "h"/"p'" = (6.63 xx 10^-34)/(6.608 xx 10^-24) = 1.003 xx 10^-10`m
= 1.003 Å = 0.1003 nm
APPEARS IN
संबंधित प्रश्न
What do you understand by the term wave-particle duality? Where does it apply?
Calculate the wavelength associated with an electron, its momentum and speed when it is accelerated through a potential of 54 V.
Define the work function of the metal.
Explain the term ‘wave-particle duality' of matter.
A parallel beam of light is incident normally on a perfectly absorbing surface. If the force exerted by the light beam on the surface is 2 x 10-7 N in 10 nanoseconds, the energy of photons hitting the surface is ____________.
The number of photons falling per second on a completely darkened plate to produce a force of 6.62 x 10-5 N is 'n'. If the wavelength of the light falling is 5 x 10-7 m, then n = ____________ x 1022. (h = 6.62 x 10-34 J-s)
According to de Broglie, wave is associated with matter ____________.
Describe in brief the different ways of electron emission from a metal surface.
What do you mean by wave frequency associated?
What do you mean by Wave number associated?
