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प्रश्न
Calculate work done when 0.5 moles of C02 is compressed isothermally and reversibly at 298 K from 100 kPa to 263.4 kPa. (R = 8.314 kJ mol-1 K-1)
संख्यात्मक
उत्तर
Given: P1 = 100 kPa, P2 = 263.4 kPa, n = 0.5, R = 8.314 x 10-3 kJ moI-1 K-1, T = 298K
`W_max = 2.3030xxnRTlog_10 P_1/P_2`
`W_max = 2.303xx8.314xx10^-3xx0.5xx298xxlog_10 100/263.4`
`=2.303xx8.314xx10^-3xx0.5xx298xx0.3796`
`= 1.083 kJ`
`= 1.1 kJ`
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