Advertisements
Advertisements
प्रश्न
Choose the correct alternative:
The minimum value of the function `|3 - x| + 9` is
पर्याय
0
3
6
9
उत्तर
9
APPEARS IN
संबंधित प्रश्न
Find the absolute extrema of the following functions on the given closed interval.
f(x) = x2 – 12x + 10; [1, 2]
Find the absolute extrema of the following functions on the given closed interval.
f(x) = 3x4 – 4x3 ; [– 1, 2]
Find the absolute extrema of the following functions on the given closed interval.
f(x) = `6x^(4/3) - 3x^(1/3) ; [-1, 1]`
Find the absolute extrema of the following functions on the given closed interval.
f(x) = `2 cos x + sin 2x; [0, pi/2]`
Find the intervals of monotonicities and hence find the local extremum for the following functions:
f(x) = 2x3 + 3x2 – 12x
Find the intervals of monotonicities and hence find the local extremum for the following functions:
f(x) = `x/(x - 5)`
Find the intervals of monotonicities and hence find the local extremum for the following functions:
f(x) = `"e"^x/(1 - "e"^x)`
Find the intervals of monotonicities and hence find the local extremum for the following functions:
f(x) = `x^3/3 - log x`
Find the intervals of monotonicities and hence find the local extremum for the following functions:
f(x) = sin x cos x + 5, x ∈ (0, 2π)
Choose the correct alternative:
The function sin4x + cos4x is increasing in the interval
Choose the correct alternative:
The maximum value of the function x2 e-2x, x > 0 is
Choose the correct alternative:
The maximum value of the product of two positive numbers, when their sum of the squares is 200, is
