मराठी

Column I Column II (A) (i) 16 cm (B) (ii) 20 cm (C) (iii) 24 cm (D) (iv) 28 cm (v) 32 cm - Mathematics

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प्रश्न

Column I Column II
(A)  (i) 16 cm
(B)   (ii) 20 cm
(C)   (iii) 24 cm
(D) (iv) 28 cm
  (v) 32 cm
जोड्या लावा/जोड्या जुळवा

उत्तर

Column I Column II
(A)  (iv) 28 cm
(B)   (i) 16 cm
(C)   (ii) 20 cm
(D) (iii) 24 cm

Explanation:

(A) Perimeter of figure = Sum of all sides

=  AB + BC + CD + DE + EF + FG + GH + HI + IJ + JK + KL + LM + MN + NA

= 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2

= 28 cm

(B) Perimeter of figure = Sum of all sides

= AB + BC + CD + DE + EF + FG + GH + HA

= 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2

= 16 cm

(C) Perimeter of figure = Sum of all sides

= AB+ BC + CD + DE + EF + FG + GH + HI + U + JA

= 2 + 2 + 2 + 2 + 2 + 2 + 2 + 24 – 2 + 2

= 20 cm

(D) Perimeter of figure = Sum of all sides

= AB + BC + CD + DE + EF + FG + GH + HI + IJ + JK + KL + LA

= 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2

= 24 cm

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पाठ 6: Mensuration - Exercise [पृष्ठ ९४]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 6
पाठ 6 Mensuration
Exercise | Q 7 | पृष्ठ ९४

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