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Complite the Following Table Given that X Varies Directly As Y . X 5 ... 10 35 25 ... Y 8 12 ... ... ... 32 - Mathematics

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प्रश्न

Complite the following table given that x varies directly as y .

x 5 ... 10 35 25 ...
y 8 12 ... ... ... 32
बेरीज

उत्तर

\[\text{ Here, x and y vary directly }  . \]
\[ \therefore x = ky\]

\[ x = 5 \text{ and } y = 8\]
\[i . e . , 5 = k \times 8\]
\[ \Rightarrow k = \frac{5}{8} = 0 . 625\]
\[\text { For y = 12 and k = 0 . 625, we have } : \]
\[x = ky\]
\[ \Rightarrow x = 12 \times 0 . 625 = 7 . 5\]
\[\text{ For x = 10 and k = 0 . 625, we have: } \]
\[x = ky\]
\[ \Rightarrow 10 = 0 . 625 \times y\]
\[ \Rightarrow y = \frac{10}{0 . 625} = 16\]
\[\text{ For x = 35 and k = 0 . 625, we have: } \]
\[x = ky\]
\[ \Rightarrow 35 = 0 . 625 \times y\]
\[ \Rightarrow y = \frac{35}{0 . 625} = 56\]
\[\text{ For x = 25 and k = 0 . 625, we have: } \]
\[x = ky\]
\[ \Rightarrow 25 = 0 . 625 \times y\]
\[ \Rightarrow y = \frac{25}{0 . 625} = 40\]
\[\text{ For y = 32 and k = 0 . 625, we have } : \]
\[x = ky\]
\[ \Rightarrow x = 0 . 625 \times 32 = 20\]

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पाठ 10: Direct and Inverse Variations - Exercise 10.1 [पृष्ठ ६]

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आरडी शर्मा Mathematics [English] Class 8
पाठ 10 Direct and Inverse Variations
Exercise 10.1 | Q 5.2 | पृष्ठ ६

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