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प्रश्न
Consider the following chemical equation I and II
- \[\ce{Mg + 2HCl -> MgCl_2 +H_2}\]
- \[\ce{NaOH +HCl -> NaCl + H_2O}\]
The correct statement about these equations is:
पर्याय
'I' is a displacement reaction and 'II' is a decomposition reaction.
'I' is a displacement reaction and 'II' is double displacement reaction.
Both 'I' and 'II' are displacement reactions.
Both 'I' and 'II' are double- displacement reactions.
उत्तर
'I' is a displacement reaction and 'II' is double displacement reaction.
Explanation:
\[\ce{Mg(s) + 2HCl(aq) ->MgCl_2(aq) + H_2(g)}\]
Magnesium displaces hydrogen in a chloride molecule in a single displacement reaction because it is more reactive than hydrogen.
\[\ce{NaOH(aq) + HCl(aq) -> NaCl(aq) + H_2O(l)}\]
The reactants in a double displacement reaction exchange ions to create new molecules. The formation of salt (NaCl) and water (HOH) in the reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is an example of a double displacement reaction, more precisely a neutralisation reaction.
संबंधित प्रश्न
Write the balanced chemical equation for the following and identify the type of reaction.
\[\ce{Magnesium(s) + Hydrochloric acid(aq) -> Magnesium chloride(aq) + Hydrogen(g)}\]
State two characteristics of the chemical reaction which takes place when dilute sulphuric acid is poured over zinc granules.
What type of reaction is represented by the following equation?
Mg + CuSO4 → MgSO4 + Cu
A strip of metal X is dipped in a blue coloured salt solution YSO4. After some time, a layer of metal Y from the salt solution is formed on the surface of metal strip X. Metal X is used in galvanisation whereas metal Y is used in making electric wires. Metal X and metal Y together form an alloy Z.
(a) What could metal X be?
(b) What could metal Y be?
(c) Name the metal salt YSO4.
(d) What type of chemical reaction takes place when metal X reacts with salt solution YSO4? Write the equation of the chemical reaction involved.
(e) Name the alloy Z.
When a black metal compound XO is heated with a colourless gas Y2, then metal X and another compound Y2O are formed. Metal X is red-brown in colour which does not react with dilute acids at all. Gas Y2 can be prepared by the action of a dilute acid on any active metal. The compound Y2O is a liquid at room temperature which can turn anhydrous copper sulphate blue.
(a) What do you think is metal X?
(b) What could be gas Y2?
(c) What is compound XO?
(d) What is compound Y2O?
(e) Write the chemical equation of the reaction which takes place on heating XO with Y2.
(f) What type of chemical reaction is illustrated in the above equation?
Name the type of reaction which is governed by the position of a metal in the metal activity series ?
To show that zinc is a more active metal than copper, the correct procedure is to:
(1) add dilute nitric acid on strips of both the metals.
(2) observe transmission of heat through strips of zinc and copper.
(3) prepare solution of zinc sulphate and hang strip of copper into it.
(4) prepare solution of copper sulphate and hang strip of zinc into it.
Classify the following reaction into different type:
Zn + CuSO4 → ZnSO4 + Cu
Complete the given chemical equation:
\[\ce{Zn(s) + CuSO4(aq) -> \underline{}\underline{}\underline{}\underline{}\underline{} + \underline{}\underline{}\underline{}\underline{}\underline{}}\]
Name the type of reaction.
State the change in colour observed in following case mentioning the reason:
A piece of zinc is dipped in ferrous sulphate solution.
