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प्रश्न
Construct a Δ PQR in which ∠ R = 90 ° , PQ = 5.2 cm and QR= 2.6 cm. Complete the figure taking PR as the line of symmetry and name the figure.
उत्तर
Steps of oonstruction:
(i) Draw a line segment QR = 2.6 cm
(ii) At R draw a perpendicular to QR.
(iii) With Q as centre and radius 5.2 cm cut an arc on perpendicular to R at P.
(iv) Join PQ . Δ PQR is the required triangle.
(v) Produce QR to S such that RS = 2.6 cm
(vi) With S as centre and radius 5.2 cm cut an arc on perpendicular to Rat P.
(vii) Join PS. Δ PSR is the triangle which is the reflection of &PQR.
Δ PQS is the required triangle and is an equilateral triangle.
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