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प्रश्न
Construct a rectangle PQRS, when its Area = 21 cm2 and length = 4.2cm
उत्तर
Since area of rectangle = 21 cm2
And, length = 4.2 cm
Breadth = Area ÷ Length = 21 ÷ 4.2 = 5 cm
Steps of construction:
1. Draw BC = 5 cm
2. Through B, draw BP such that ∠B = 90°
3. From BP, cut BA = 4.2 cm
4. With A and C as centres and radii 5 cm and 4.2 cm respectively, draw arcs cutting each other at D.
5. Join AD and CD.
Thus, ABCD is the required triangle.
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