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प्रश्न
Construct a triangle using the following data: PQ + PR = 10.6 cm, QR = 4.8 cm and ∠R = 45°
उत्तर
PQ + PR = 10.6 cm, QR = 4.8 cm and ∠R = 45°
Steps of construction:
1. Draw a line segment QR = 4.8 cm
2. With Q as centre, construct ∠SQR = 45°
3. Cut QT = 10.6 cm on QS.
4. Join TR.
5. Draw perpendicular bisector of TR which cuts QT at P.
6. Join PR.
Thus PQR is the required triangle.
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संबंधित प्रश्न
In ∆ PQR, l(PQ) = 6 cm, l(QR) = 3.8 cm, l(PR) = 4.5 cm
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