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प्रश्न
Construct ΔDEF such that DE = EF = 6 cm, ∠F = 45° and constructs its circumcircle.
बेरीज
उत्तर
Rough figure:
DE = EF
∴ ∠DFE = ∠EDF = 45°
∴ ∠DFE = 90°
Steps of construction:
- Construct ∆DEF of the given measurement.
- Draw the perpendicular bisectors of side DE and side EF of the triangle.
- Name the point of intersection of perpendicular bisectors as C.
- Join seg CE.
- Draw circle with centre C and radius CE.
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Construction of the Circumcircle of a Triangle
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